WebJul 14, 2024 · 维护一个集合(也可以用优先队列),从 1 到 n 遍历,每次将左边界等于 i 的取值范围的右边界放入集合。 每次贪心取出最小的右边界,这个区间对应的 a 就是 i。 因为集合中的所有取值范围左边界都是小于等于 i ,最小的右边界也一定大于等于 i,如果最小的右边界小于 i,那么往后遍历 i 一直增大,那么这个区间就永远不满足条件,就会多出一 … WebChanges Start enabling automation of treatments for gs-cv (commit: b2d657e) ()Add PngWatcherVerticle (commit: 982ae31) ()Start automatic image classification (commit: …
E. Split Into Two Sets(种类并查集+染色法判二分图)
Web2 hours ago · FRIDAY, April 14, 2024 (HealthDay News) -- Early-career doctors were more likely to make mistakes when they had long work weeks or extended shifts, new research reveals. WebCF1702E 题解 题目链接(CF,洛谷) 强烈推荐博客中观看。 题意 给你 $n$ ($n$ 为偶数,$2 \le 2 \cdot 10^5$)个,数对。 数对中的每个数字都是从 $1$ 到 $n$ 的。 现在问你是否能将这些数对分到两个集合中。 使得每个集合中没有任何一个重复的数字。 比如有下面这四个数对:$\{1, 4\}, \{1, 3\}, \{3, 2\}, \{4, 2\}$。 那么可以这样分配这些数对: 第一个集合 … cabinet office newcastle
origo CF-1702 8"搖擺對流扇 - ORIGIN
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