2024 Django get latest for each group

Django get latest for each group

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WebMay 11, 2024 · obj = Model.objects.filter (testfield=12).order_by ('id').latest ('id') Filter based on what field you need - in this case is testfield. Model.objects.filter (testfield=12) In order to get the latest record, first you need to sort the queryset. So that it knows to return the last record based on a criteria. Now, order the results base on your ... WebAug 21, 2015 · 1. I have a little problem with getting latest foreign key value in my django app. Here are my two models: class Stock (models.Model): ... class Dividend (models.Model): date = models.DateField ('pay date') stock = models.ForeignKey (Stock, related_name="dividends") class Meta: ordering = ["date"] I would like to get latest …

Django selecting top n records per group using ORM

WebGROUP BY and Select MAX from each group in Django, 2 queries Raw gistfile1.txt ''' given a Model with: category = models.CharField (max_length=32, choices=CATEGORY_CHOICES) pubdate = models.DateTimeField (default=datetime.now) Fetch the item from each category with the latest pubdate. ''' Webfrom django.db.models import Q group_dict = Model.objects.values ('business_id').annotate (max_date=Max ('date')).order_by () params = Q () for obj in group_dict: params = (Q (business_id__exact=obj ['business_id']) & Q (date=obj ['max_date'])) qs = Model.objects.filter (params) This link can help u. giant negative thermal expansion

Django Query: Group by field and get the latest entry per group

Web[Answered]-Django Query Get Last Record with a Group By-django score:-1 Instead .order_by ('-month') [:1] it's better to use .order_by ('month').last () or .order_by ('-month').first () (or earliest / latest for dates). Of course when grouping you can use order_by: WebDec 16, 2024 · Get top n records for each group with Django queryset Ask Question Asked 2 years, 3 months ago Modified 2 years, 3 months ago Viewed 1k times 1 I have a model like the following Table, create table `mytable` ( `person` varchar (10), `groupname` int, `age` int ); And I want to get the 2 oldest people from each group. WebJan 31, 2024 · 1 Answer. Sorted by: 2. You may try this: MyModel.objects.filter ( #prepare subquery which has max dates per month #and limit resultset only to those dates date__in = Subquery ( MyModel.objects.annotate ( truncated_to_month = TruncMonth ('date') #used to group by truncated to month date ).values ( 'truncated_to_month' ).annotate ( … frozen breaded chicken patties air fryer

Django, group by one field, only take the latest / max of each group ...

django - How to use group by and get every record in each group ...

WebMay 19, 2024 · yes, you can go ahead and test it. and print and check the queryset returned. I have a similar use case (considering the same model in the question), instead I had to fetch the latest record for each seller on each date. So I did this :- latest_sale = Sales.objects.order_by ("Saler", "-Date").distinct ("Saler") – Abhijeet Anand Shah. WebApr 1, 2015 · If you happen to be using PostGreSQL, you can use Django's interface to DISTINCT ON: recent_cakes = Cake.objects.order_by ('bakery__id', '-baked_at').distinct ('bakery__id') As the docs say, you must order by the same fields that you distinct on. As Simon pointed out below, if you want to do additional sorting, you'll have to do it in … giant nerf footballWebMay 31, 2024 · Last record of each id ?! each record has only one unique id. But if you mean you want the object with the greatest id I think there are 2 ways to get the last object: queryset = model.objects.filter (id__in= [1, 5, 7]).order_by ('id').last () Or you can do this: queryset = model.objects.filter (id__in= [1, 5, 7]).latest ('id') Share giant networking

"WebI can use a queryset to return the latest update time for each location: latest_updates = Locations.objects.values ('location').annotate (max_date=Max ('update_time')).order_by ('location') but this only returns the location and max update_time when I'm looking for the entire row - num_01, num_02, num_03. " - Django get latest for each group

Django get latest for each group

[Answered]-Django Query Get Last Record with a Group By-django

WebDjango orm get latest for each group. I am using Django 1.6 with Mysql. class Student (models.Model): username = models.CharField (max_length=200, unique = True) class … WebJan 24, 2024 · To signify this, in Django positional arguments to .distinct () can be passed only in Postgresql ). In Django we can do this with QuerySet like this: Portfolio.objects.order_by ().order_by ( 'code', # first, cause we want to group by this value '-created' # descending order, latest / max will be first ).distinct ('code')

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WebJul 5, 2024 · I want to get the latest score record for each student. I have tried: Score .objects ( 'student' .annotate (latest_date= Max 'date' )) Copy. and: Score … WebDec 11, 2024 · 1 Answer Sorted by: 0 The dataset you need can be efficiently built with prefetch_related. userinfo = UserInfo.objects.all ().prefetch_related ("attendancerecord_set") for ui in userinfo: for ar in ui.addendancerecord_set.all (): print (ar) in template code

WebAug 14, 2024 · You can use slice operator to limit the query to a number of records. For example, limit to 10 latest records: UserData.objects.filter (user_id__in=user_list, date_created__lte=start_date) [:10]. Django querysets are lazy so this won't query all records and then slice it - it will only query 10. – vinkomlacic Aug 16, 2024 at 9:39 Add a … WebMar 1, 2024 · We can select top n per group with help of Subquery. Firstly, let's get top n Purchases per customer top_n_purchases_per_customer = Purchases.objects.filter ( customer=OuterRef ('customer') ).order_by ('-field_of_interest') [:10] Next, we can select Purchases with matching ids from the top 10 per each customer.

WebHow do I write a Django ORM query that: groups the Requests by user, filters the Requests based on req_text, and also, select the max id of the resulting result set. So for each user, I will return one row which matches the filter condition and also has the greatest id. django django-orm Share Follow asked Aug 4, 2011 at 11:02 jeffreyveon

WebMar 19, 2024 · Django ORM group by, and find latest item of each group (window functions) class Cake (models.Model): baked_on = models.DateTimeField (auto_now_add=True) cake_name = models.CharField (max_length=20) Now, there are multiple Cake s baked on the same day, and I need a query that will return me a monthly …

WebJan 25, 2024 · It's also easy to get an individual vendor / locale's current value with Costs.objects.filter(vendor_id=1, locale_id=10).latest(). What I'm interested in getting is all of the latest cost values for each vendor / locale combo. So essentially running the latest() function over each combination and getting a list / queryset as a result. frozen breaded chicken patty sandwich recipesWebJul 26, 2013 · Imagine we have the Django ORM model Meetup with the following definition: class Meetup (models.Model): language = models.CharField () date = models.DateField (auto_now=True) I'd like to fetch the latest meetup for each language. It would seem you could use Django Aggregates to make this lookup easy: giant net lights for roofWebDjango ORM - Get latest record for group; Filtering Django Query by the Record with the Maximum Column Value; Django Raw Query: Making Count query with group BY … giant netherlandsWebMar 29, 2024 · 1 Answer. for each in People.objects.all (): score = models.CharField (verbose_name=each.title, max_length=4) Firstly even if the loop works there would only be one score field in the end. Next a Django model is the reflection of a Database table. Ever heard of a table having an arbitrary number of columns (atleast a good normalized table)? giant network technology limitedWeb1 looks like you need to add empty order_by () by the default-ordering-or-order-by in the result query can be added extra fields to the group by. try it: Market.objects.values ('slug').annotate (Max ('active')).order_by () Share Improve this answer Follow answered Oct 23, 2024 at 21:42 Brown Bear 19.4k 10 53 75 Add a comment Your Answer frozen breaded fish brandsWebSep 10, 2024 · A simple way to do this in a single query is to annotate each photo with the latest date for the related person and then filter by the annotation. This should return all desired PersonPhoto in a queryset. from django.db.models import Max, F PersonPhoto.objects.annotate ( latest=Max ('person__personphoto__date_captured') … frozen breaded eggplantWebOct 7, 2015 · Now, i want to get the problems count for latest test for each name. For example if my table data is. name date problems count foo 10.10.15 50 foo 10.09.15 30 bar 10.07.15 23 foo 10.03.15 54 bar 05.03.15 31 foo 10.01.15 97 Then i would like to get. frozen breaded clams