WebEn el caso de sustancias gaseosas se puede emplear la ecuación del gas ideal (Sec. 10.4) para hacer conversiones entre concentración (en molaridad, M) y presión (en atm): PV = nRT, por tanto M = 1n>V2 = 1P>RT2 Con respecto a las sustancias A y B, por consiguiente, [A] = 1PA>RT2 y [B] = 1PB>RT2 Y, por tanto, las velocidades de las reacciones … WebA) The entropy change is negative because a larger molecule (Cl₂O₇) is converted into two smaller molecules (Cl₂ and O₂). B) The entropy change is zero because the reactants and products are all gases. C) The entropy change cannot be determined because the temperature is not specified.
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WebFirstly, as the air enters the lungs, it is humidified by the upper airway and thus the partial pressure of water vapour (47 mmHg) reduces the oxygen partial pressure to about 150 … WebDec 22, 2015 · P O2 = 0.30moles 1.2moles ⋅ 1.56 atm = 0.39 atm P CO2 = 0.15moles 1.2moles ⋅ 1.56 atm = 0.20 atm The values don';t add up to give 1.56 atm because they must be rounded to two sig figs, the number of sig figs … dolina 11 sarajevo
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WebThe Henry’s law constant for N2 in 25 °C water is thus 14.75 * 10-4 mol>L2> 0.78 atm = 6.1 * 10-4 mol>[email protected] If the partial pressure of N2 is doubled, Henry’s law predicts that the solubility in water at 25 °C also doubles to 9.50 * 10-4 M. Bottlers use the effect of pressure on solubility in producing carbonated beverages ... WebSo let's start by writing the expression for Q. Right? Which is just like K E Q. But we use that when we're not sure if we're at equilibrium yet. So we can predict if we are okay, but still products overreacted. It's raised to the coefficients. Okay, so our expression for Q will be this And once we find Q We're going to compare it to K. P., which is 26. WebAug 19, 2014 · The equilibrium concentrations are [N₂O] = 1.00 mol/L; [O₂] = 0.50 mol/L; [NO] = 1.00 mol/L. Kc = 2.0. First, write the balanced chemical equation with an ICE table. 2N₂O + O₂ ⇌ 4NO I/mol·L⁻¹: 0; 0; 3.00 C/mol·L⁻¹: +2 x; + x; -4 x E/mol·L⁻¹: 2 x; x; 3.00 - 4 x At equilibrium, [N₂O] = 2 x mol/L= 1.00 mol/L. So x = 0.50 dolina 5c okulista