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Then show that a2 – 4a+ 7i 0. hence find a5

Splet03. apr. 2024 · a 2 + 8 = 4a Formula used: (a + b) 2 = a 2 + b 2 + 2ab Calculation: a 2 + 8 = 4a Squaring on both side ⇒ (a 2 + 8) 2 = (4a) 2 ⇒ a 4 + 16a 2 + 64 = 16a 2 ⇒ a 4 = – 64 ----1 a … SpletTo show: A 2 – 4A + 7I = O and also find A 3. Proof: Firstly, we calculate A 2. Putting the value in given equation, we get. A 2 – 4A + 7I = 0 = RHS. Now, we have to find the A 3. OR. …

linear algebra - Matrix Inverse Proof $A^2 − 3A + I = 0

Splet19. jan. 2024 · Show that `A =[{:(5,3),(-1,-2):}]` satisfies the equation `A^(2)-3A-7I=0` and hence find the value of `A^(-1)` so you spin my head right round https://jdmichaelsrecruiting.com

ALGEBRA HW 10 - CSU

Splet04. jun. 2014 · If A = , show that A 2 - 6A + 17I = 0. Hence, find A-1. Asked by Topperlearning User 04 Jun, 2014, 01:23: PM Expert Answer We are given that A = . Now, A 2 - 6A + 17I … Splet04. nov. 2024 · Hence Solve the system of equations; x - 2y = 10 2x - y - z = 8 -2y + z = 7 class-12 Share It On 1 Answer +2 votes answered Nov 4, 2024 by Darshee (49.8k points) selected Nov 16, 2024 by Aanchi Best answer A = 1 (−1 − 2) − 2 (−2 − 0) = −3 + 4 = 1 A is non-singular, therefore A−1 exists The given equations can be written as: Splet16. mar. 2024 · Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo. team publons

Ex 4.5, 16 - Verify A3 - 6A2 + 9A -4I = O and hence find A-1 - teachoo

Category:Ex 4.5, 13 - Show that A2 - 5A + 7I = O. Hence find A-1 - Ex 4.5

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Then show that a2 – 4a+ 7i 0. hence find a5

Ex 4.5, 16 - Verify A3 - 6A2 + 9A -4I = O and hence find A-1 - teachoo

SpletThe correct option is D5 I 3Find the value of A 2 - 4 A:Given that A = 1 2 2 2 1 2 2 2 1A 2 = 1 2 2 2 1 2 2 2 1 1 2 2 2 1 2 2 2 1 = 9 8 8 8 9 8 8 8 94 A = 4 1 2 2 2 1 2 2 2 1 = 4 8 8 8 4 8 8 8 … Splet26. sep. 2015 · [-1 2 ] then show that A 2 + 4A +7I = 0. Using this result find A 3 Share with your friends 2 Follow 0 Pooja Khanna, Meritnation Expert added an answer, on 26/9/15 …

Then show that a2 – 4a+ 7i 0. hence find a5

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SpletIf a = [ (2,-1,1), (-1,2,-1), (1,-1,2)] Verify That A3 − 6a2 + 9a − 4i = O And Hence Find A−1 - Mathematics Shaalaa.com CBSE Commerce (English Medium) Class 12 If a = [ (2,-1,1), (-1,2,-1), (1,-1,2)] Verify That A3 − 6a2 + 9a − 4i = O And Hence Find A−1 - Mathematics Advertisement Remove all ads Advertisement Remove all ads SpletQ. Suppose a Matrix A satisfies A2−5A+7I=0 If A5 =aA+bI, then the values of 2a + b is. Q. Show that A=[ 5 3 −1 −2] satisfies the equation A2 - 3A - 7I = 0 and hence find the value of A−1. Q. If A2 =3A−2I and A8 =aA+bI, then a+b is Q. For the matrix A=[3 2 1 1], the values of a and b such that A2+aA+bI=0 are View More

SpletCayley Hamilton theorem states that the characteristic equation is satisfied by A ∴ Replacing λ with A ∴ A 2 − 4 A − 5 I = 0 -------- (2) Given : A 5 − 4 A 4 − 7 A 3 + 11 A 2 − A − 10 I ------ (3) ∴ Dividing Equation (3) by Equation (2) SpletHence proved. Given: A 2 − 5 A + 7 I = 0. ⇒ A 2 = 5 A − 7 I ... (1) ⇒ A 3 = A ( 5 A − 7 I) (Multilpying by A on both sides) ⇒ A 3 = 5 A 2 − 7 A I. ⇒ A 3 = 5 ( 5 A − 7 I) − 7 A [From …

SpletAnswer: If A3 −A2 +A−I= 0, then (A2 −A+I)A= A3 −A2 +A= I= A3 −A2 +A= A(A2 −A+I) so A−1 = A2 −A+I. ♣ (b): If Ais a square matrix satisfying A7 = 0, find (I−A)−1 in terms of A. … SpletYou have to show that any matrix that satisfies the equation A 2 + 2 A + I = 0 is invertible. – 5xum Mar 2, 2014 at 22:49 Add a comment 5 Answers Sorted by: 4 The inverse of A is almost certainly not A. You have A 2 + 2 A = − I, or A ( A + 2 I) = − I. Multiplying by − 1 you get A ( − A − 2 I) = I Hence the inverse of A is − A − 2 I. Share Cite

Splet19. feb. 2012 · So, the characteristic polynomial of A is p ( t) = t 2 − 4 t − 5. You are interested in the polynomial P ( t) = t 5 − 4 t 4 − 7 t 3 + 11 t 2 − t − 10, evaluated at A. We …

SpletIf , show that A2– 5A + 7I = O. Hence find A–1. We have A2= A.A = . So A2– 5A + 7I = Hence A2– 5A + 7I = 0 ∴A.A – 5A = -7I Now post multiply with A-1 So A.A.A-1-5A.A-1= -7I.A-1 … soyoustart promoSplet23. mar. 2024 · Find the adjoint of the matrix A = (A.I.C.B.S.E. 2010) Solution: Here A = Now A 11 = Co-factor of 2 = 3, A 12 = Co-factor of – 1 = – 4, A 21 = Co-factor of 4 = 1 and … team pto calendar in outlookSplet30. avg. 2024 · Best answer We have, Therefore, A2 – 4A + 7I A2 = 4A – 7I Thus A3 = A.A2 = A (4A – 7I) = 4 (4A – 7I) – 7A = 16A – 28I – 7A = 9A – 28I and so A5 = A3A2 = (9A – … team pudseySpletThen show that A 2 – 4A + 7I = O. Using this result calculate A 5 also. Advertisement Remove all ads Solution We have A 2 = [ 2 3 - 1 2] [ 2 3 - 1 2] = [ 1 12 - 4 1] – 4A = [ - 8 - 12 … so you see the writing on the wallSpletIf A=[ 3−112], show that A 2−5A+7I=0. Hence, find A −1. Medium Solution Verified by Toppr We have, [ 3−112] ∴A 2=AA= [ 3−112][ 3−112]=[ 8−553] So, A 2−5A+7I= [ 8−553]−5[ … so your the punk i heard about fartSpletYou'll get a detailed solution from a subject matter expert that helps you learn core concepts. Question: Let A be an (n × n) matrix which satisfies the equation A2 ? 2A + I = … team pto calendar sharepointSpletA 2 = 1 12 -4 1-4A = -8 -12 4 -8 7I = 7 0 0 7 add these three values u will get 0. 0 team public