Then show that a2 – 4a+ 7i 0. hence find a5
SpletThe correct option is D5 I 3Find the value of A 2 - 4 A:Given that A = 1 2 2 2 1 2 2 2 1A 2 = 1 2 2 2 1 2 2 2 1 1 2 2 2 1 2 2 2 1 = 9 8 8 8 9 8 8 8 94 A = 4 1 2 2 2 1 2 2 2 1 = 4 8 8 8 4 8 8 8 … Splet26. sep. 2015 · [-1 2 ] then show that A 2 + 4A +7I = 0. Using this result find A 3 Share with your friends 2 Follow 0 Pooja Khanna, Meritnation Expert added an answer, on 26/9/15 …
Then show that a2 – 4a+ 7i 0. hence find a5
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SpletIf a = [ (2,-1,1), (-1,2,-1), (1,-1,2)] Verify That A3 − 6a2 + 9a − 4i = O And Hence Find A−1 - Mathematics Shaalaa.com CBSE Commerce (English Medium) Class 12 If a = [ (2,-1,1), (-1,2,-1), (1,-1,2)] Verify That A3 − 6a2 + 9a − 4i = O And Hence Find A−1 - Mathematics Advertisement Remove all ads Advertisement Remove all ads SpletQ. Suppose a Matrix A satisfies A2−5A+7I=0 If A5 =aA+bI, then the values of 2a + b is. Q. Show that A=[ 5 3 −1 −2] satisfies the equation A2 - 3A - 7I = 0 and hence find the value of A−1. Q. If A2 =3A−2I and A8 =aA+bI, then a+b is Q. For the matrix A=[3 2 1 1], the values of a and b such that A2+aA+bI=0 are View More
SpletCayley Hamilton theorem states that the characteristic equation is satisfied by A ∴ Replacing λ with A ∴ A 2 − 4 A − 5 I = 0 -------- (2) Given : A 5 − 4 A 4 − 7 A 3 + 11 A 2 − A − 10 I ------ (3) ∴ Dividing Equation (3) by Equation (2) SpletHence proved. Given: A 2 − 5 A + 7 I = 0. ⇒ A 2 = 5 A − 7 I ... (1) ⇒ A 3 = A ( 5 A − 7 I) (Multilpying by A on both sides) ⇒ A 3 = 5 A 2 − 7 A I. ⇒ A 3 = 5 ( 5 A − 7 I) − 7 A [From …
SpletAnswer: If A3 −A2 +A−I= 0, then (A2 −A+I)A= A3 −A2 +A= I= A3 −A2 +A= A(A2 −A+I) so A−1 = A2 −A+I. ♣ (b): If Ais a square matrix satisfying A7 = 0, find (I−A)−1 in terms of A. … SpletYou have to show that any matrix that satisfies the equation A 2 + 2 A + I = 0 is invertible. – 5xum Mar 2, 2014 at 22:49 Add a comment 5 Answers Sorted by: 4 The inverse of A is almost certainly not A. You have A 2 + 2 A = − I, or A ( A + 2 I) = − I. Multiplying by − 1 you get A ( − A − 2 I) = I Hence the inverse of A is − A − 2 I. Share Cite
Splet19. feb. 2012 · So, the characteristic polynomial of A is p ( t) = t 2 − 4 t − 5. You are interested in the polynomial P ( t) = t 5 − 4 t 4 − 7 t 3 + 11 t 2 − t − 10, evaluated at A. We …
SpletIf , show that A2– 5A + 7I = O. Hence find A–1. We have A2= A.A = . So A2– 5A + 7I = Hence A2– 5A + 7I = 0 ∴A.A – 5A = -7I Now post multiply with A-1 So A.A.A-1-5A.A-1= -7I.A-1 … soyoustart promoSplet23. mar. 2024 · Find the adjoint of the matrix A = (A.I.C.B.S.E. 2010) Solution: Here A = Now A 11 = Co-factor of 2 = 3, A 12 = Co-factor of – 1 = – 4, A 21 = Co-factor of 4 = 1 and … team pto calendar in outlookSplet30. avg. 2024 · Best answer We have, Therefore, A2 – 4A + 7I A2 = 4A – 7I Thus A3 = A.A2 = A (4A – 7I) = 4 (4A – 7I) – 7A = 16A – 28I – 7A = 9A – 28I and so A5 = A3A2 = (9A – … team pudseySpletThen show that A 2 – 4A + 7I = O. Using this result calculate A 5 also. Advertisement Remove all ads Solution We have A 2 = [ 2 3 - 1 2] [ 2 3 - 1 2] = [ 1 12 - 4 1] – 4A = [ - 8 - 12 … so you see the writing on the wallSpletIf A=[ 3−112], show that A 2−5A+7I=0. Hence, find A −1. Medium Solution Verified by Toppr We have, [ 3−112] ∴A 2=AA= [ 3−112][ 3−112]=[ 8−553] So, A 2−5A+7I= [ 8−553]−5[ … so your the punk i heard about fartSpletYou'll get a detailed solution from a subject matter expert that helps you learn core concepts. Question: Let A be an (n × n) matrix which satisfies the equation A2 ? 2A + I = … team pto calendar sharepointSpletA 2 = 1 12 -4 1-4A = -8 -12 4 -8 7I = 7 0 0 7 add these three values u will get 0. 0 team public